Solving a Physics Problem: Forces, Acceleration, and Work

AI Thread Summary
The discussion focuses on solving a physics problem involving a child pulling a sled with a dog, analyzing forces, acceleration, and work. The normal force is calculated as the difference between the child's force and the frictional force, resulting in 8.563 N. The acceleration of the system is determined to be 0.428 m/s² based on the normal force and total mass. The work done by the child over a distance of 7 meters is calculated to be approximately 59.94 J. The term "normal" refers to the perpendicular force exerted by a surface on an object resting on it.
logglypop
Messages
47
Reaction score
0
A child pulls a 15kg sled containing a 5kg dog along a straight path on a horizontal surface. He exerts a force of a 55N on the sled at an angle of 20 degree above the horizontal. The coefficient of friction between the sled and the surface is 0.22 .
Find:a) normal force of the surface on the system , b) the acceleration of system, c) the work done by the child as the system move 7m.
This is how i approach them

a)normal force = Force of the child exert - Force of friction
55cos20 - .22( (15+5)9.8 ) = 8.563 N

b)normal force= ma
8.563N = ( 15+5 )a
a=.428m/s^2

c)W=Fd W=8.563(7)= 59.94J

give me suggest if I am make a mistake
 
Last edited:
Physics news on Phys.org
What do you understand "normal" to mean when talking about surfaces?
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top