Solving a Simple RL Circuit: Find My Fault!

  • Thread starter Thread starter rbwang1225
  • Start date Start date
  • Tags Tags
    Circuit Rl circuit
rbwang1225
Messages
112
Reaction score
0

Homework Statement


8.jpg

circuit.jpg


The Attempt at a Solution


[itex]V-R_1I_1-LdI_L/dt=0, V-R_1I_1-R_2I_2=0, I_1=I_L+I_2[/itex]
My result is [itex]I_L=(V/R_1)(1-exp[-tR_1R_2/(R_1+R_2)L])[/itex]
Where is my fault?
Any help is appreciated!
 
on Phys.org
have you learned laplace transforms? it is probably unnecessary in this case but the safest way to do problems like this.
 
This being a first order circuit (only one type of reactive component), you know that the resulting waveforms for all the transient values (currents, voltages) will involve decaying exponential functions with a particular time constant. If you can determine the initial conditions and the final conditions, then the exponential functions will connect the two. Simple! The only really tricky bit is determining the time constant, [itex]\tau[/itex].

The problem statement says that the switch is initially closed (prior to time t = 0). So what is the steady-state current through the inductor, and hence the initial current for time t=0+? When the switch is opened, what paths are available for current to flow? So what components determine the time constant? What's the eventual value of the inductor current?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
1K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K