How can I solve this standard integral using substitution?

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To solve the integral $$ \int _0^ {\pi/2} 2 \sin(x) \cos(x) \sqrt {1+\sin^{2}(x) } dx $$, a substitution of ##u=\sin^2(x)+1## is suggested, leading to ##du=2\sin(x)\cos(x)dx##. However, it's crucial to change the limits of integration when substituting. The indefinite integral of ##u^{1/2}## is noted to be incorrectly calculated in the discussion. A step-by-step calculator is recommended for practice, but understanding the integral's fundamentals is emphasized as essential for exams.
Andrea Vironda
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Homework Statement
Solve this integral
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I think parametrization is needed
Hi,
I'd like to integrate this function: $$ \int _0^ {\pi/2} 2 \sin(x) \cos(x) \sqrt {1+\sin^{2}(x) } dx $$.
I think I should introduce some substitution but I'm not sure. How should I proceed?
 
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I could tell you, but you will learn better if you try it on your own. What have you tried?
 
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In my opinion I could define ##u=\sin^2(x)+1##, so ##du=2\sin(x)\cos(x)dx##.
Then ##\int_0^{\pi/2}\sqrt{u}du=2(\sqrt2-1)## but this is not the right solution.
 
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Don't forget to change the limits of integration, unless you substitute u back into the expression after integration.

This is what I'm getting for the corresponding indefinite integral.

Screen Shot 2021-01-04 at 4.23.42 AM.png


If I may, I would suggest a step-by-step calculator to guide you.

https://www.integral-calculator.com

That calculator cannot help you on exams, but it could help you practice solving integrals.
 
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That's a good substitution, but I don't think you did the integral correctly. What is the indefinite integral of u^(1/2)?
 
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You don't need a substitution or anything, just note that ##(1+\sin^2{x})' = 2\sin{x} \cos{x}## :smile:
 
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Solving integrals is an art
 

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