Solving a Statics Problem with F=80N

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SUMMARY

The discussion centers on solving a statics problem involving a force F of 80.0 N and its components along bars AB and AC. The force F is directed straight down, with bar AB at a 30-degree angle and bar AC at a 70-degree angle from the vertical. Participants clarify that the components of the force should not be added directly, as they are not in static equilibrium, and emphasize the importance of using the dot product correctly to resolve the components.

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  • Basic skills in resolving forces in two dimensions
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hey all. I'm having problems with what should be a simple statics problem.

"The Magnitude of force F is 80.0 N. What are the madnitude of its components a) F\ab and b) F\ac that are parallel to the bars AB and AC respectively."

The picture: Force F pointing straight down. bar AB pointing 30 left of straight up (NW), and and bar AC pointing 70 degrees left of straight up (NW also).

I know i need to use the dot product somehwhere, but I can't determine what i need to do it with respect to. But I did rotate the problem 90 degrees CCW, and had the resulting equation:

|80*F\ac|cos110 + |80*F\ab|cos150=0

additional question: will F\ab + F\ac = 80. When adding up all those forces this problem doesn't seem to be in static equallibrium...

Thanks
 
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No, adding the force onto each bar will not equal the original force.

Each component part of your equation is right, but I do not understand why you are trying to add the components. When you see a force written as F=#i+#j, the 'i' and 'j' are 90 degrees apart.
 

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