Solving an 1100kg Car's Work Output on a 50m Hill

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SUMMARY

The work produced by the engine of an 1100 kg car climbing a 50 m hill with a final speed of 25 m/s is calculated to be 882,750 J. This total work (W) is the sum of the work done against gravitational potential energy (W1) and the kinetic energy at the top of the hill (W2). The equations used include W = F(d) and F = ma, where the force is derived from the car's mass and gravitational acceleration. The solution involves calculating both potential and kinetic energy contributions to determine the total work output.

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Homework Statement



A car of mass 1100kg starts from rest at sea level and climbs a hill of altitude of 50 m. At the top of the hill the car has a speed of 25 m/s.

The work produced by the engine of the car is?


Homework Equations


W= F(d)
F= ma

The Attempt at a Solution


W = Force x 50m
Yea, I have tried this problem about 8 different ways, but it says the correct answer is 882,750 J and I cannot figure out how to get that from the numbers given.

Any help would be great, thanks.
 
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PhilCam said:

Homework Statement



A car of mass 1100kg starts from rest at sea level and climbs a hill of altitude of 50 m. At the top of the hill the car has a speed of 25 m/s.

The work produced by the engine of the car is?


Homework Equations


W= F(d)
F= ma

The Attempt at a Solution


W = Force x 50m
Yea, I have tried this problem about 8 different ways, but it says the correct answer is 882,750 J and I cannot figure out how to get that from the numbers given.

Any help would be great, thanks.

There are two different things here that require work for the engine:

W = W1 + W2

One of them is the potential energy overcome by climbing the hill, W1. This would be enough if the object came to rest at the top of the hill, but it's didn't. It still has a velocity. From this, you might be able to guess what W2 is.
 
Thank you very much, I got it.
 

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