Solving an Equation: Rearranging Numbers Around

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Homework Help Overview

The discussion revolves around the mathematical identity \( e^{i\pi} + 1 = 0 \) and the task of rearranging it to derive \( i^i = e^{-\frac{\pi}{2}} \). Participants are exploring the manipulation of complex numbers and exponential forms.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss isolating terms and taking square roots, questioning the next steps after manipulating the equation. There are inquiries about alternative representations of \( \sqrt{e^{i\pi}} \) and \( \sqrt{-1} \). Suggestions include raising both sides of the equation to the power of \( i \) and considerations about the implications of changing square roots to fractional exponents.

Discussion Status

The conversation is ongoing, with participants providing hints and suggestions without reaching a consensus. There is an active exploration of different mathematical transformations and their potential outcomes.

Contextual Notes

Participants are navigating the complexities of manipulating exponential and imaginary numbers, with some expressing uncertainty about notation and steps in the process.

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Homework Statement


Okay, yesterday in class my teacher gave me this identity [tex]e^{i\pi }+1=0[/tex]
and she wants me to rearrange the numbers around, so I can get this [tex]i^{i}= e^{-\frac{\pi}{2}}[/tex]


Homework Equations

and

The Attempt at a Solution


I know that if Isolate the 1 to the other side and take the square root of each sides I will have this [tex]\sqrt{e^{i\pi }}= \sqrt{-1}[/tex]
But this is the question what do I do after that ?
 
Last edited:
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xvtsx said:

Homework Equations

and

The Attempt at a Solution


I know that if Isolate the 1 to the other side and take the square root of each sides I will have this [tex]\sqrt{e^{i\Pi }}= \sqrt{-1}[/tex]
But this is the question what do I do after that ?

Do you know another way to write

[tex]\sqrt{e^{i \pi}}[/tex]?

Do you know another way to write

[tex]\sqrt{-1}[/tex]?
 
Hi xvtsx! :smile:

(have a pi: π and try using the X2 tag just above the Reply box :wink:)

Raise each side of your last equation to the power of i. :smile:
 
Hmm.. do I raise to the power of i after I change the square root for [tex]\frac{1}{2}[/tex] and multiple it with [tex]iπ[/tex] ?
 
Last edited:
(what happened to that π i gave you? :redface:)

Yes, (eiπ/2)i = … ? :smile:
 
sorry for the pi part, but I use the latex editor and it only gaves that one xD.. thanks by the way. :)
 

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