Solving an Equation: x = vo t + ½ a t2

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Homework Help Overview

The discussion revolves around the equation x = vo t + ½ a t², which is related to kinematics and describes motion under constant acceleration. Participants are exploring the implications of this equation in different contexts, particularly in relation to distance and time.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are examining the relationship between variables in the equation, questioning the validity of their assumptions about distance and acceleration. There is a discussion about the implications of using different forms of the equation and how they relate to specific scenarios.

Discussion Status

The conversation is ongoing, with participants providing insights and raising questions about the variables involved. Some guidance has been offered regarding the interpretation of the equations, but there is no clear consensus on the correct approach or solution at this time.

Contextual Notes

Participants are navigating through the implications of different variables and equations, with some confusion about the relationships between them. There is a noted absence of explicit use of all relevant equations, which may affect the understanding of the problem.

Arun Raja
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Homework Statement


http://puu.sh/dzuq5/629a29dd48.png

Homework Equations


x = vo t + ½ a t2
2 a x= v2 - vo2[/B]

The Attempt at a Solution


1/4 d = vo t + ½ a t2[/B]
multiply equation by 4,
d=4 ut+ 2a t2

so I am thinking answer is 4u, but it is 2u.
 
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Does that mean you think ½ a t2 in the ¼ d case is the same as 2 a t2 (different t ?) in the distance =d case ?
 
no. But I am not sure of the correct way too. so pls help .
 
Well, if we go through "all variables and given/known data" in "problem statement" and "relevant equations", we see u, d, x, v0, a, t and v.

In your attempt at solution, you have ¼ d = vo t + ½ a t2 . Correctly, if I assume vo is u .

You don't use the second relevant equation. Why not? What does it mean ? What is v ?

All this is for the ¼ d case. What changes for the d case ? And what stays the same ?
 
Arun Raja said:
x = vo t + ½ a t2
Do you know a different equation relating distance, speed and acceleration?
 
Look at this in energy terms instead. It took kinetic energy E to get to d/4, so how much energy is needed to get to d?
And finally, what is the relation between kinetic energy and speed?
 

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