Solving an Integral Using Residue Theorem

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SUMMARY

The integral in question is solved using the residue theorem, focusing on the singularity points where Z^2 equals an integer, leading to e^(2*pi*i*n) equating to 1. The discussion highlights that the integration path is a circle centered at (0,0) with a radius R that lies between √n and √(n+1) for each positive integer n. The number of poles enclosed by each circular path varies depending on the value of n, indicating a complex relationship between the integral and its singularities.

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Homework Statement



Hey guys.
So I got this integral I need to solve, of curse using the residue theorem.
The thing is, that I don't understand the curve.
I know that whenever Z^2 = integer, this function has a singularity point because e^(2*pi*i*n) = 1.
But again, I'm not sure what this curve has enclosed in.

Thanks.

Homework Equations





The Attempt at a Solution

 

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This is, actually, an "infinite sequence" of problems! Each path is a circle, with center (0,0) of radius R which lies between [itex]\sqrt{n}[/itex] and [itex]\sqrt{n+1}[/itex] for each positive integer n. I suspect that you will find that the number of poles inside each path depends on n.
 

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