Solving an Optics Problem: Convex Lens, Plane Mirror, and Virtual Image

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The discussion revolves around solving a geometrical optics problem involving a convex lens and a plane mirror. The user applies the lens formula to determine the image distance, concluding that the image is located 30 cm to the left of the lens. This image then acts as an object for the plane mirror, resulting in a final virtual image located 60 cm to the right of the mirror. The user expresses confusion over the provided answer options, believing them to be incorrect. Ultimately, the user confirms they have found the correct solution with assistance from others.
thunderhadron
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Hi friends,

I am sticking in a problem of Geometrical OPTICS,
The problem is as https://fbcdn-sphotos-e-a.akamaihd.net/hphotos-ak-snc6/285225_2890687243573_1306065782_n.jpg

Attempt -

Here for the convex lens applying the lens formula
1/v - 1/u = 1/f

so, 1/v = 1/u + 1/f

1/v = - 1/15 + 1/30 (since I have taken the left side as negative)

after solving this v = - 30 cm.

The image of the object will be 30 cm. far from the lens and left side of the lens and now this image will work as an object for the plane mirror. Its distance from the plane mirror will be 45 cm which is left of the it so it is real as far as I am concerned.

So from the mirror property now its Final image will be 60 cm right of it and will be virtual.

I think that the answer of the question is given wrong cause it is giving the answer options (B) & (C).

Please friends help me in solving this issue.
Thank you all in advance.
 
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Draw the rays going through the lens and then reflected by the mirror. Do they really intersect in front of the mirror?

ehild
 
Thank you very much ehild.

I got the answer.
 
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