Solving Baby Rudin Chapter 1 Problem 16

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Homework Help Overview

This discussion revolves around a problem from Baby Rudin, Chapter 1, specifically Problem 16, which involves proving statements about points in R^k based on their distances. The problem requires exploring conditions under which a point z can exist relative to two other points x and y, given certain distance constraints.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to prove three statements regarding the existence and uniqueness of point z based on the distances between x, y, and z. Some participants suggest using geometric reasoning to visualize the problem, while others question the adequacy of this approach compared to an analytical one.

Discussion Status

The discussion is ongoing, with some participants providing geometric insights into the problem. The original poster has made attempts at parts of the problem but seeks further clarification, particularly on proving the first part. There is no explicit consensus yet on the best approach to take.

Contextual Notes

The problem involves specific conditions on distances (2r, d) and requires careful consideration of the geometric arrangement of points in R^k. The original poster expresses uncertainty about the uniqueness of z in part 2 and the implications of the conditions in part 3.

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Homework Statement


This is a problem from baby rudin in Chapter 1, I've done all of them except this(problem 16).
suppose k>=3,x,y belongs to [R][/k],|x-y|=d>0,and r>0.prove:
(1)if 2r>d, there are infinitely many z belong to R(k) such that |z-x|=|z-y|=r.
(2)if 2r=d, there is exactly one such z.
(3)if 2r<d, there is no such z.

The Attempt at a Solution


I have done a part of this question. I can't prove (1). About (2), when 2r=d, let z=(x+y)/2, then |z-x|=|z-y|=d/2. However, I can't prove it is unique. About (3), suppose there exists such z, then by thereom 1.37 in baby rudin we have 2r=|z-x|+|z-y|>=|x-y|=d, which contradicts the fact that 2r<d.

May somebody help me!
 
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OMG,will somebody tell me why there is not anybody replied?
 
jerryczj said:
OMG,will somebody tell me why there is not anybody replied?
If someone tells you why no one has replied, then someone would have replied, making the need for an answer to your question unnecessary.:biggrin:

For the three parts of your question, you are dealing with three points in Rk: x, y, and z.

Draw a picture of x and y at a distance of d apart. Now add a point z. For part 2, it's pretty clear from the geometry that there is only one place that z could be. For part 3, it's also pretty clear that there could not be any point z that satisfies the given condition.

For part 1, the geometry shows that there are an infinite number of possible locations for z.
 
For the three parts of your question, you are dealing with three points in Rk: x, y, and z.

Draw a picture of x and y at a distance of d apart. Now add a point z. For part 2, it's pretty clear from the geometry that there is only one place that z could be. For part 3, it's also pretty clear that there could not be any point z that satisfies the given condition.

For part 1, the geometry shows that there are an infinite number of possible locations for z.[/QUOTE]
I appreciate it very much. However, I don't think it is an analytic way. Any way, thank you for so kind to a noob.
 
But drawing a sketch shows you the geometry, which should get you thinking about how you would write up a more analytical explanation.
 

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