Solving Basic Stokes Theorem Homework on Ellipse

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Homework Help Overview

The discussion revolves around applying Stokes' Theorem to find the circulation of a vector field around a specified curve, specifically an ellipse in the xy-plane. The vector field is given as F = x^2i + 2xj + z^2k, and the curve C is defined by the equation 4x^2 + y^2 = 4.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of the curl of the vector field and the normal vector to the surface. There is confusion regarding the normal vector's definition and whether parameterization of the ellipse is necessary. Questions arise about setting up the double integral for the problem.

Discussion Status

Some participants provide guidance on the dot product and suggest that the problem may be simplified by recognizing the constant nature of the integrand. However, there is still uncertainty regarding the correct interpretation of the normal vector and the setup of the integral.

Contextual Notes

Participants note confusion regarding the gradient of the function defining the ellipse and its relation to the normal vector in the context of Stokes' Theorem. There is an emphasis on understanding the geometric interpretation of the problem.

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Homework Statement


Use the surface integral in stokes theorem to find circulation of field F around the curve C.
F=x^2i+2xj+z^2k
C: the ellipse 4x^2+y^2=4 in the xy plane, counterclockwise when viewed from above



Homework Equations


stokes theroem: cirlulation=double integral of nabla X F.n d(sigma)


The Attempt at a Solution


i got nabla cross F is 2k
for the normal, aint it just k? coz I am getting confused by if i let g(x,y,z)=4x^2+y^2-4=0 (the elispe)
isnt n=grad(g)=8xi+2yj
im confused with this

also should i parameterize the ellipse?
im not sure how I am meant to set the double integral out?
im really lost, any help please?
 
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Right, curl(F)=2k and n=k. What's the dot product? You want to integrate that dx*dy over the interior of the ellipse 4*x^2+y^2=4. From here on the problem is not that different than finding the area of an ellipse or a circle using a double integral. Take a deep breath and try it. If you're clever, you'll notice the integrand is a constant so you don't have to integrate at all if you know a formula for the area of the region.
 
thanks, its just isn't the normal grad(g), or am i getting this confused with somethig else?
 
You are getting it confused with something else. You want the normal to the region in the x-y plane, which is k, as you said. grad(4x^2+y^2-4) is normal to the elliptical cylinder 4x^2+y^2-4=0.
 
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