Solving Battery Problem: Transport 2.6 kg Chocolate up 1000m

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The discussion focuses on calculating the amount of chocolate that can be transported using a 4.5 Volt, 1600 mAh battery to lift it 1000 meters. The initial calculation of energy in Joules was incorrect, but after correcting the conversion, the energy available is determined to be 25,920 Joules. To find the mass that can be lifted, participants are encouraged to calculate the energy required to lift 1 kilogram over 1 meter. The conversation emphasizes the need for relevant equations to solve the problem effectively. Ultimately, the goal is to determine how many kilograms of chocolate can be transported to the summit using the available energy.
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Homework Statement



A 4.5 Volt is labeled: 4.5 V ; 1600 mAh (milliamperehour). This battery is the energy source of a chocolate lift. Find the number of kilograms of chocolater you can Transport with this lift up to the summit. The summit is 1000 meter above the valley Station.

Homework Equations



The solution is 2.6 kg

The Attempt at a Solution



I assume that my start is correct:

J = C * V

so

J = (1600 mAh / (3600 sec * 1000)) * 4.5 V

isn't it?

Is the solution 0.002 J then? What did I wrong?
How do I have to go on?

Thanks in advance!
 
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Now I found out my fault:

1 Ah = 3600 As = 3600 C
C = 1600/1000 * 3600 = 5760
V = 4.5

So:
J = 5760 * 4.5 = 25 920 J

Now my new question:
How can I find out the kilogram with help of the Joule?
 
You find a relevant equation for bringing a mass from the Valley Station to a summit that is 1000 m higher !

Ask yourself: how many Joules do I need to lift 1 kilogram over 1 m ?

Under "relevant equations" a potential helper expects to find the equations you think have to be brought into deal with the problem. "The answer is.." is not a relevant equation! Give me something better !
 
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