Solving Beams with Triangular Loads - Why the Third Point?”

[remi_c]

Hi. I can't understand one thing in mechanics.

I am trying to learn how to solve beams in mchanics.

I have a triangular load (a load which changes constantly). Why is the point of application of the net force in the one third of the triangle's base?

While dividing a right triangle into 3 parts, we don't get two equal fields...

Thanx

 

[PhanthomJay]

Hi. I can't understand one thing in mechanics.

I am trying to learn how to solve beams in mchanics.

I have a triangular load (a load which changes constantly). Why is the point of application of the net force in the one third of the triangle's base?

While dividing a right triangle into 3 parts, we don't get two equal fields...

Thanx

You are dividing the triangle into two parts equal in area, or equal in weight. This location of the resultant at 1/3 the distance from the fat end is the center of gravity of the triangular load, which you can calculate as a good exercise.