Solving Charge Accumulated from Scuffing Feet: Magnitude of Force

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Homework Help Overview

The discussion revolves around calculating the magnitude of the force on an electron due to a person's accumulated static charge from scuffing feet on a rug. The problem involves understanding electrostatic forces and Coulomb's law in the context of static electricity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Coulomb's law to determine the force on a single electron at a specified distance from a charged person. There is uncertainty about which charges to use in the calculations and how to correctly apply the formula.

Discussion Status

Some participants have provided guidance on using the charge of the person and the charge of an electron in the calculations. There is an ongoing exploration of the correct application of Coulomb's law, with multiple interpretations of the variables involved.

Contextual Notes

Participants are navigating the specifics of the problem, including the conversion of microcoulombs to coulombs and the implications of distance in the force calculation. There is mention of previous parts of the problem that have been solved, which may influence the current discussion.

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Homework Statement


Part A (which I already got right) A person scuffing her feet on a wool rug on a dry day accumulates a net charge of -72.1 uC. How many excess electrons does this person get?
Part B (Which is what I need help on) Given the static charge buildup in the previous question, what is the magnitude of the force on an electron at a distance 6.03 m from the person?

Homework Equations


So i thought that what you would do is simply find how many coulombs are in an electron, which is 1.6E-19 C. Then convert the uC to C and you would get .000072 C or 7.2E-5 C. So i divided the 7.2E-5 by the 1.6E-19 and got 4.5E14 which was the correct answer. But the part I need help with is finding the magnitude of the force. I would think I could just use coulombs law but I am not really sure what my q1 and q2 would be. Would I use 7.2E-5 and the 4.5E14? or would i use something else?


The Attempt at a Solution


I did
F=((8.9E9)(4.5E14)(7.2E-5))/6.03^2 and got an answer of 7.9E18 N. which was wrong. not sure where i went wrong
 
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Yes colombs law, its asking you what force a SINGLE electron would experience, 6.03m away from the person..

Try treating the person as a single charge. Find out what the charge of an electron is, and try colombs law.
 
Well the charge of a single electron is 1.6E-19 C. so would it be then
F=(8.9E9)(1.6E-19)/6.03^2? cause i tried that and it was still wrong. Would the equation just be then kQ/r^2 or would it be kQ^2/r^2
just not sure
 
Colombs law is F = \frac{kQ_1Q_2}{r^2}

It measures the force two charges exerts on each other at a given distance r. So if one charge is the charge of an electron, the other charge is?
 
thank you so much. got it. so it was using the charge of the net charge from what i was given. the 7.2uC
 
I'm stuck on this problem too. Did you end up using
(k)(charge of girl)(charge of electron)/r^2?
 
you do k(charge of how many she accumulated)(charge of electron)/r^2
 

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