Solving Collision Problem: 10.0g Bullet & 5.00lg Block

[Dejey]

Homework Statement

a 10.0-g bullet is fired into a stationary block of wood (m=5.00 lg). the bullet imbeds into the block. the speed of the bullet-plus-wood combination immediately after the collision is 0.600 m/s. what was the original speed of the bullet

Homework Equations

v= (m1)(v1a)/((m1)+(m2)
I=delat p
i am not 100% if you would even use that, or if that is what you need. i tryed it out and i will post it in about 10min. but the answer was given to me, and when i tested it out, i was wrong

The Attempt at a Solution

to be added soon.

 

[Kurdt]

v= (m1)(v1a)/((m1)+(m2)

If you tried to work out the answer using this then you would be wrong. You're trying to find the speed of the bullet. the equation you've given is arranged for the speed of the bullet and block which you already know. Start with the conservation of momentum equation and try rearranging it again.