Solving Collisions & ZMFs Homework: Mass 4 Particle Deflection

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SUMMARY

The discussion focuses on solving a non-relativistic collision problem involving two particles with relative masses of 4 and 1. By applying conservation of momentum and energy principles, it is demonstrated that the larger particle can be deflected at most by an angle of arcsin(1/4). The equations derived include momentum conservation in both x and y directions, leading to a quadratic equation that confirms the maximum deflection angle. This analysis is crucial for understanding particle dynamics in collision scenarios.

PREREQUISITES
  • Understanding of non-relativistic mechanics
  • Familiarity with conservation laws (momentum and energy)
  • Knowledge of trigonometric functions and their properties
  • Ability to solve quadratic equations
NEXT STEPS
  • Study the principles of conservation of momentum in two-dimensional collisions
  • Learn about the implications of mass ratios in particle collisions
  • Explore the derivation of angles in elastic collisions
  • Investigate the application of quadratic equations in physics problems
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Students and educators in physics, particularly those focusing on mechanics and collision theory, will benefit from this discussion. It is also valuable for anyone seeking to deepen their understanding of particle interactions in non-relativistic contexts.

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Homework Statement


A particle of relative mass 4 travels at velocity v, and collides with a stationary particle with relative mass 1. By considering the zero momentum frame, show that the larger particle can be deflected by an angle of arcsin(1/4) at the most.

(Note this is a non-relativistic problem)


Homework Equations





The Attempt at a Solution

 
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The problem can be solved by using conservation energy and momentum.
Lat v1i is the initial velocity of mass 4 and v2i is the initial velocity of mass 1. You can wright three equations.
4v1i + 0 = 4v1f*cos(theta1) + v2f*cos(theta2) [ moments along the x direction]...(1)
4v1f*sin(theta1) = v2f*sin(theta2)[y-components of momentum]...(2)
0.5*4*v1i^2 = 0.5*4*v1f^2 + 0.5*v2f^2 [conservation of energy}...(3)
Now rewright equation(1) as 4v1i - 4v1f*cos(theta1) = v2f*cos(theta2) and square it. Now square equation (2) and add it to the above equation.After simplification you will get
5v1f^2 -8v1i*v1f*cos(theta1) + 3v1i^2 = 0. Here v1i is constant. For real root of this quadritic equation we must have [64v1i^2cos^2(theta) -4*5*3v1i^] > 0
[[64v1i^2{1 - sin^2(theta)} -60v1i^] > 0 Taking 4v1i^2 common we get
16 - 16sin^2(theta) - 15 > 0 or 1 - 16sin^2(theta) > 0 or sin(theta) < 1/4. That is the required result.
 

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