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## Homework Statement

I am a little confused on the steps to take to solve these kinds of functions.

Solve:

cosh z = 2i

## The Attempt at a Solution

We were given identities for sinh z = 0 and cosh z = 0 and also other identities like

cosh(z) = cos (iz)

So cos (iz) = 2i

cos (z) would be 2i for (Pi/2 + 2kPi) right? So cos(iz) = i(Pi/2 + 2kPi) = 2i?

However, this doesn't look right.