Solving Derivatives: A Puzzling Experience

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Homework Help Overview

The discussion revolves around a derivative problem involving the equation \(\frac{dy}{2} = 2x\), which the original poster claims is derived from the function \(y = x^2\). There is confusion regarding the representation of \(dy\) and its relationship to changes in \(x\) and \(y\).

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the validity of the equation and question the meaning of \(dy\) without a corresponding \(dx\). Some express confusion about the relationship between \(dy\) and changes in \(x\) and \(y\), while others reflect on the implications of the equation being presented in a non-standard form.

Discussion Status

There is ongoing exploration of the implications of the original equation, with some participants suggesting that it may be incorrectly presented. Guidance has been offered regarding the necessity of a corresponding \(dx\) for meaningful analysis, and there is acknowledgment of the equation's lack of clarity.

Contextual Notes

Some participants note that the original poster's presentation of the problem may be misleading or incomplete, leading to confusion about the relationship between \(dy\) and \(dx\). There are references to the need for proper definitions in the context of derivatives.

vanmaiden
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Homework Statement


I was messing around online when I found this: [itex]\frac{dy}{2}[/itex] = 2x. This was derived from the function y = x2. I had never really seen anything like this before. When I solved for "dy," I got 4x. However, for example, when x changes from 0 to 2, the y changes from 0 to 4. Interestingly enough, "dy" is represented as being 4x and not just 4. Can someone point out what I did wrong?


Homework Equations


y = x2
[itex]\frac{dy}{2}[/itex] = 2x


The Attempt at a Solution


Pretty much explained in the "problem statement" by accident.
 
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You find a lot of things on the internet. Shockingly, not all of them are true.
 
SteamKing said:
You find a lot of things on the internet. Shockingly, not all of them are true.

That is true without a doubt! lol. How would I go about solving something like this though? I am given delta x and the derivative and have to find delta y. It all seems very interesting.
 
You wouldn't. The equation is meaningless. You cannot have a "dy" without a corresponding "dx". In terms of "non-standard analysis", we would say that the left side of the equation is an infinitesmal while the right side is not. That can't happen.

Since you say "This was derived from the function [itex]y = x^2[/itex]" I suspect that it was supposed to be
[tex]\frac{dy}{dx}= x^2[/tex]
 
vanmaiden said:

Homework Statement


I was messing around online when I found this: [itex]\frac{dy}{2}[/itex] = 2x. This was derived from the function y = x2. I had never really seen anything like this before. When I solved for "dy," I got 4x. However, for example, when x changes from 0 to 2, the y changes from 0 to 4. Interestingly enough, "dy" is represented as being 4x and not just 4. Can someone point out what I did wrong?


Homework Equations


y = x2
[itex]\frac{dy}{2}[/itex] = 2x
The equation above should be dy = 2x dx
vanmaiden said:

The Attempt at a Solution


Pretty much explained in the "problem statement" by accident.
 
vanmaiden said:

Homework Statement


I was messing around online when I found this: [itex]\frac{dy}{2}[/itex] = 2x. This was derived from the function y = x2. I had never really seen anything like this before. When I solved for "dy," I got 4x. However, for example, when x changes from 0 to 2, the y changes from 0 to 4. Interestingly enough, "dy" is represented as being 4x and not just 4. Can someone point out what I did wrong?


Homework Equations


y = x2
[itex]\frac{dy}{2}[/itex] = 2x


The Attempt at a Solution


Pretty much explained in the "problem statement" by accident.

Here the point is, in my personal opinion

dy = 4*x

x is a variable but as the problem ( lamely presented ) offers

dy=0

and

thus
x=4*0

x=0 alwyas no matter what

Either wrongly presented or gives us the line equation

x = 0
 
stallionx said:
Here the point is, in my personal opinion

dy = 4*x

x is a variable but as the problem ( lamely presented ) offers

dy=0

and

thus
x=4*0

x=0 alwyas no matter what

Either wrongly presented or gives us the line equation

x = 0

Thank you
 
vanmaiden said:
Thank you

You are quite Welcome :)
 
stallionx said:
Here the point is, in my personal opinion

dy = 4*x
As HallsOfIvy already pointed out, this equation is meaningless, so there is not much point in analyzing it further.
stallionx said:
x is a variable but as the problem ( lamely presented ) offers

dy=0

and

thus
x=4*0

x=0 alwyas no matter what

Either wrongly presented or gives us the line equation

x = 0
 

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