Solving Determinants: Tips for Midterm Exam

  • Context: Undergrad 
  • Thread starter Thread starter salman213
  • Start date Start date
  • Tags Tags
    Determinant
Click For Summary

Discussion Overview

The discussion revolves around strategies for solving determinants in the context of a linear algebra midterm exam. Participants explore different methods for finding specific elements of a matrix inverse without directly calculating the inverse, particularly focusing on Cramer's rule and cofactor expansion.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant seeks assistance with a specific determinant problem and expresses concern about the efficiency of finding the matrix inverse during an exam.
  • Another participant suggests that if the inverse is known, the desired element can be found using the third row of the inverse matrix multiplied by a specific vector, emphasizing the importance of the determinant.
  • A different participant introduces the concept of using cofactors, proposing that the cofactor of a specific element divided by the determinant could yield the desired result.
  • Another participant clarifies the use of Cramer's rule, explaining how to find the solution vector using determinants of modified matrices.
  • A later reply indicates that both the cofactor method and Cramer's rule lead to the same result, suggesting that either approach could be valid for the problem at hand.

Areas of Agreement / Disagreement

Participants express differing views on the preferred method for solving the determinant problem, with some advocating for Cramer's rule while others support the cofactor approach. No consensus is reached on which method is superior or preferred for the exam.

Contextual Notes

Participants do not fully agree on the terminology used, such as "cof(2,3)," and there is some ambiguity regarding the specific steps involved in applying Cramer's rule versus using cofactors. The discussion reflects varying levels of understanding and confidence in the methods proposed.

Who May Find This Useful

Students preparing for linear algebra exams, particularly those focusing on determinants and matrix operations.

salman213
Messages
301
Reaction score
1
Hi, I have a midterm tomorrow for my Lin Alg course and I was doing some review probs and I can't seem to understand this one..

http://img119.imageshack.us/img119/239/39786409wb4.jpg

Can someone help me and explain how to do this one!

I know I can just find the whole vector

x1,x2,x3,x4 by just multiplying by A^-1 but on a midterm I don't thinK I will want to waste time and find the inverse of such a matrix if there is another way to approach this problem.
 
Last edited by a moderator:
Physics news on Phys.org
IF you knew A-1, then x3 would just be third row of A-1 time that vector- in other words, since the given vector has a 1 in the second place, zeros elsewhere, it would be the number in the third row, second column of A-1. Can you think of a way of finding that number only? (Especially since you are given the determinant!)
 
thanks a lot

Cof (a) (2,3)
------------ = would be that specific element
det a

right?
!
 
I'm not sure what you mean by "cof(2,3)", but, since you're given a Cramer system AX = B (A is a regular matrix), the solution is X = (x1, x2, x3, x4), where xi = Dj / D, where Dj is the determinant of the matrix which is created by substituting the j-th column of the matrix A with B, and D = det A.
 
Yea someone asked that question today in morning cause exam is in afternoon and he said to do it that way ur saying.. so i guess i get what u said thanks!

but i treid what i was saying and it gives same answer since basically Cofactor of A of the 2,3 term divided by determinant of A is exactly the 3,2 term in the A^-1 and therefore thas what we want. It gives same answer so I guess you can do it etiehr way but I am sure he would want us to use cramers rule to get like ur saying

det A with 3rd column replaced with 0,1,0,0 over determinant of A

thanks!
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
34K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
5
Views
1K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K