Solving differential equations

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The differential equation f''(x) = sin(x) is solved with initial conditions f(0) = 0 and f'(0) = 1. The integration process yields f'(x) = -cos(x) + 2 and subsequently f(x) = -sin(x) + 2x. The constants C1 and C2 are determined to be 2 and 0, respectively. The solution f(x) = -sin(x) + 2x is confirmed as correct. The discussion includes a minor clarification regarding the notation of initial conditions.
chapsticks
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Homework Statement




Solve the following differential equation:

f"(x)=sinx

x(0)=0, x'(0)=1

Homework Equations



x(0)=0, x'(0)=1

The Attempt at a Solution




f"(x)=sin(x)
integrate,
f'(x)=-cos(x)+C1
f'(0)=-cos(0)+C1=1 => C1=2
C1=2
f'(x)=-cos(x)+2
f(x)=-sin(x)+2x+C2
f(0)=-sin(0)+C2=0 => C2=0

=>
f(x)=-sin(x)+2x
 
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It is correct.

ehild
 
chapsticks said:

Homework Statement




Solve the following differential equation:

f"(x)=sinx

x(0)=0, x'(0)=1
Minor point, but this should be f(0) = 0, f'(0) = 1.
chapsticks said:

Homework Equations



x(0)=0, x'(0)=1

The Attempt at a Solution




f"(x)=sin(x)
integrate,
f'(x)=-cos(x)+C1
f'(0)=-cos(0)+C1=1 => C1=2
C1=2
f'(x)=-cos(x)+2
f(x)=-sin(x)+2x+C2
f(0)=-sin(0)+C2=0 => C2=0

=>
f(x)=-sin(x)+2x
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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