Solving dy/dx=x-y | Learn how to integrate y without respect to anything

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Homework Help Overview

The discussion revolves around the integration of the expression dy/dx = x - y, with a focus on understanding how to integrate y without respect to a variable. Participants are exploring the implications of this integration in the context of solving a differential equation.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the challenge of integrating y without knowing its functional form. There are attempts to manipulate the differential equation and suggestions to use substitutions to simplify the problem. Questions arise about the feasibility of integrating both sides directly and the nature of nonhomogeneous differential equations.

Discussion Status

The discussion is active, with participants providing various insights and suggestions for approaching the problem. Some guidance has been offered regarding substitutions and the nature of the equation, but there is no explicit consensus on a single method or solution path.

Contextual Notes

There is an acknowledgment of the original poster's uncertainty and the potential complexity of the problem, particularly regarding the integration of y and the classification of the differential equation as nonhomogeneous.

computerex
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Homework Statement



[tex]\int (x-y)[/tex]

What is [tex]\int y[/tex] ? I don't mean [tex]\int y dy[/tex].

The Attempt at a Solution



[tex]dy/dx = x-y[/tex]
[tex]y + dy = x dx[/tex]
[tex]\int y + \int dy = \int x dx[/tex]
[tex]\int y + y = x^2/2 + c[/tex]

I am stuck at this point because I don't know how to integrate y without respect to anything...If that even makes sense.

EDIT:

Nvm...I am stupid xD

[tex]\int x dx - \int y dx[/tex]
 
Last edited:
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computerex said:
EDIT:

Nvm...I am stupid xD

[tex]\int x dx - \int y dx[/tex]

That still doesn't help you though. How exactly do you plan on integrating [itex]\int y(x) dx[/itex] when you don't know what [itex]y(x)[/itex] is?

You can't solve this differential equation just by integrating both sides. Instead, try using the substitution [itex]u=x-y[/itex] to rewrite the DE in terms of [itex]u(x)[/itex] and [itex]u'(x)[/itex].
 
gabbagabbahey said:
Instead, try using the substitution [itex]u=x-y[/itex] to rewrite the DE in terms of [itex]u(x)[/itex] and [itex]u'(x)[/itex].
That will result in another nonhomogeneous ODE. A tiny bit simpler perhaps, but still nonhomogeneous.

computerex: What have you been taught regarding solving nonhomogeneous differential equations?
 
D H said:
That will result in another nonhomogeneous ODE. A tiny bit simpler perhaps, but still nonhomogeneous.

Something about separable ODE's appeals to me though:wink:
 
Depends on the OP's background. The original problem can be rewritten as

[tex]\frac{dy}{dx} + y = x[/tex]

The homogeneous and particular solutions can be read off just by inspection.
 

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