Solving equation with two imaginary roots

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The equation -x² + 2(k+2)x - 9k = 0 has two imaginary roots when the discriminant is less than zero. To determine the values of k that yield imaginary roots, one must analyze the relationship between the coefficients of the polynomial. Specifically, the condition for imaginary roots arises when the expression 2(k+2)² - 4(-9k) < 0 is satisfied, leading to a conceptual understanding of the polynomial's behavior rather than mere calculation.

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lordvoo
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1. -xn2+2(k+2)x-9k=0
Has two imaginary roots, what are the values of k?


Attempted to break it down and use the quadratic formula but wasn't able to do it. Would like a pointer in the right direction of where to begin to solve it.

Thanks
 
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look at the quadratic formula and ask yourself:

What is the relationship between the polynomial coefficients to have imaginary roots?
 
lordvoo said:
1. -xn2+2(k+2)x-9k=0
Has two imaginary roots, what are the values of k?





Attempted to break it down and use the quadratic formula but wasn't able to do it. Would like a pointer in the right direction of where to begin to solve it.

Thanks

Yes, or I could say just look at that quadratic formula and ask yourself what terms must be real (take it that k is real) and what terms can be imaginary, it is a conceptual question not one of calculation.

Have made one typo? - I suppose that should be maybe

-x2 + 2(k+2)x -9k= 0

Check you haven't made another. :wink:
 

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