Solving Euler Theorem Doubts with Partial Derivatives

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SUMMARY

This discussion focuses on applying Euler's Theorem using partial derivatives to solve specific mathematical problems. The first problem involves demonstrating that the equation x²(d²z/dx²) + 2xy(d²z/dxdy) + y²(d²z/dy²) = 0 holds true for the function z = xf(y/x) + g(y/x). The second problem requires proving that PT(d²z/dx²) + 2(d²z/dxdy) + (d²z/dy²) = 2/(x-y) for the function z = (xy)/(x-y). Participants emphasize the importance of using LaTeX for clarity in mathematical expressions.

PREREQUISITES
  • Understanding of partial derivatives and their notation
  • Familiarity with Euler's Theorem in the context of multivariable calculus
  • Proficiency in using LaTeX for mathematical notation
  • Knowledge of chain rule differentiation
NEXT STEPS
  • Study the application of Euler's Theorem in multivariable calculus
  • Learn advanced techniques for computing partial derivatives
  • Explore the simplification of complex derivative expressions
  • Practice using LaTeX for formatting mathematical equations
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Mathematics students, educators, and professionals in fields requiring advanced calculus, particularly those working with partial derivatives and multivariable functions.

Nina2905
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firstly, all d's i use will mean partial derivative 'do' because i don't have the font installed. sorry :(

please help me with these.. u got to use euler theorem
1. if z= xf(y/x) + g(y/x), show that x2(d2z/dx2) + 2xy(d2z/dxdy) + y2(d2z/dy2) =0
2. if z= (xy)/(x-y), PT (d2z/dx2) + 2(d2z/dxdy) + (d2z/dy2) = 2/(x-y)

thanks...
 
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First, it's not a matrer of having "fonts" installed, just use LaTex with [ tex ] and [ /tex ] (without the spaces) beginning and ending. To see LaTex commands, click on any formula on this board.

I'm not sure which "Euler Theorem" you mean (there are many). It looks to me like like you only need to differentiate.

If z= xf(y/x)+ g(y/x), then
[tex]\frac{\partial z}{\partial x}= f(y/x)+ x f'(y/x)(-y/x^2)+ g'(y/x)(-y/x^2)[/tex]
by the chain rule. Doing that again,
[tex]\frac{\partial^2 z}{\partial x^2}= [f'(y/x)(-y/x^2)]+ [f'(y/x)(-y/x^2)+ xf"(y/x)(-y/x^2)^2+ xf'(y/x)(2y/x^3)]+ g"(y/x)(-y/x^2)^2+ g'(y/x)(-2y/x^3)][/tex]
Of course, that can be simplified a lot.
 

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