Solving Exp(-3ln(x)): Finding the Next Step | Homework Help

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The discussion focuses on simplifying the expression exp(-3ln(x)). The correct next step is identified as exp(ln(x^-3)) = x^-3, confirming option (a) as accurate. Option (b), which suggests exp(-ln(x^3)) = -x^3, is incorrect because it misapplies the properties of exponents and logarithms. The confusion arises from misunderstanding how to handle the negative sign in exponentiation. The consensus is that option (a) is the valid simplification.
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Homework Statement



Got to part of a problem where I have exp(-3ln(x)) and I am confused as to whether the next step is:

a) exp(ln(x^-3)) = x^-3

or

b) exp(-ln(x^3)) = -x^3


I think the correct step is (a) but not certain, any help would be great :)
 
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SteveDC said:

Homework Statement



Got to part of a problem where I have exp(-3ln(x)) and I am confused as to whether the next step is:

a) exp(ln(x^-3)) = x^-3

or

b) exp(-ln(x^3)) = -x^3

I think the correct step is (a) but not certain, any help would be great :)
Yes (a) is the correct result.

For (b):

exp(-ln(x^3)) = ##\displaystyle \frac{1}{e^{\ln (x^3)}}\ ## → ##\displaystyle \ \frac{1}{x^3} \ .##
 
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SteveDC said:
b) exp(-ln(x^3)) = -x^3
Here it appears you're saying ##e^{-a} = -e^a##, that you can simply pull the minus sign out front, which you probably know isn't correct.
 
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