- #1
Monocerotis
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Solving Exponential Equations SO CONFUSED ?
I'm trying to solve problems like these
a) 2(3y-2) = 18
b) 27(33x+1) = 3
c) 2x+2 - 2x = 48
d) 10z+4 + 10z+3 = 11
Laws of exponential values.
b) 2(3y-2) = 18
6y-2 = 18
Stuck/Confused.
Maybe there's something fundamental I'm forgetting or making overly complicated. If you divide 18 by 3 to make it 6 so then you could just work with the exponential values to solve for y, wouldn't you also have to do the same thing to 2(3y-2) (or) 6y-2
For say a problem like this
3(5x+1) =15
15x+1 = 15
Now you have both bases balanced, you can work to solve for x
x+1 = 0 ?
x = 0 - 1
x = -1
That would then mean 150 = 15, which doesn't work out because anything to an exponential value of 0 is 1, correct ?
Homework Statement
I'm trying to solve problems like these
a) 2(3y-2) = 18
b) 27(33x+1) = 3
c) 2x+2 - 2x = 48
d) 10z+4 + 10z+3 = 11
Homework Equations
Laws of exponential values.
The Attempt at a Solution
b) 2(3y-2) = 18
6y-2 = 18
Stuck/Confused.
Maybe there's something fundamental I'm forgetting or making overly complicated. If you divide 18 by 3 to make it 6 so then you could just work with the exponential values to solve for y, wouldn't you also have to do the same thing to 2(3y-2) (or) 6y-2
For say a problem like this
3(5x+1) =15
15x+1 = 15
Now you have both bases balanced, you can work to solve for x
x+1 = 0 ?
x = 0 - 1
x = -1
That would then mean 150 = 15, which doesn't work out because anything to an exponential value of 0 is 1, correct ?