Solving for Bode Critical Frequency: Guide and Equation Explanation

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SUMMARY

The discussion focuses on determining the critical frequency from a given Bode plot represented by the transfer function G(jω) = 2/(-ω² + 162jω + 320). The user initially misinterprets the equation leading to an invalid solution involving the square root of a negative number. The correct approach involves substituting s = jω, transforming the transfer function to G(s) = 2/(s² + 162s + 320), which reveals that the denominator has negative-valued roots corresponding to the angular frequencies of interest.

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fractal01
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I am given a bode plot and have to label the cutoff frequency on there.
G(jw)=2/(-w^2 +162jw +320)

I got this equation where w is the critical frequency:
70922=81^2 + (170 -(w^2/4))

I am sure that this is wrong since I get the sqrt of a negative number for w.

It would be really great if someone could help!
 
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2 is equivalent to (jω)2. So let s = jω and your transfer function becomes:
$$\frac{2}{s^2 + 162s + 320}$$
The denominator has a pair of negative valued roots which should correspond to (angular) frequencies of interest.
 

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