Solving for capacitance and frequency in Xc = 1/(2πFC)

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RanCor
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This is the first time I've used this forum and i really could use someones help on how to solve for C in my formula instead of Xc

My formula is

Xc = 1 / (2PiFC) "Pi is, pi yea know, 3.14", (not 2 other unknowns)

Instead of solving for Xc i need to be able to solve for C and i don't know how to go about doing that...

any sort of help would be appreciated :)

Also... i looked down the page alilbit and i also need a formula on how to solve for F

If someone could show me how that's done so i wouldn't have to ask anyone anymore i would be very happy
 
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Multiply both sides of the equation by C:

CX_c = 1/(2πF)

Then divide both sides by X_c:

C = 1/(2πFX_c)
 
By the way, it is considered bad netiquette to post this in several sub-fora on the same forum. I understand that you could be in a hurry to get this solved, but if you post it in the appropriate sub-forum (homework help), people will get to it and assist you just as quickly.