Solving for Current in Resistor 2 at t = 4.00 ms

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SUMMARY

The discussion focuses on calculating the current in resistor R2 (10.0 kΩ) at t = 4.00 ms after the switch in a circuit with an ideal battery (20.0 V) and a capacitor (0.600 µF) is opened. The user initially calculated the current to be 0.000478 A. Verification of this result is sought, indicating the importance of showing all calculation steps for accuracy. The steady state is reached before the switch is opened, which is crucial for understanding the circuit behavior.

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Homework Statement


In the figure below, R1 = 5.0 k, R2 = 10.0 k, C = 0.600 µF, and the ideal battery has emf script e = 20.0 V. First, the switch is closed a long time so that the steady state is reached. Then the switch is opened at time t = 0. What is the current in resistor 2 at t = 4.00 ms?
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Homework Equations





The Attempt at a Solution


I did everything and got .000478. Is this correct? If not, I'll go through all of my steps.
 
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Show your steps.
 

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