Solving for f'(x) using the chain and quotient rules

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Homework Help Overview

The problem involves finding the derivative of the function f(x) = (x²)/sin²(x) using the chain and quotient rules. Participants are discussing the application of these calculus concepts to compute f'(x).

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt to apply the quotient rule and chain rule to differentiate the function. There are variations in the expressions for f'(x) presented, and some participants question the notation used for sin²(x).

Discussion Status

The discussion includes multiple attempts at expressing the derivative, with some participants providing slightly different formulations. There is no explicit consensus on the correct form of f'(x), and the notation for sin²(x) has been noted as a point of clarification.

Contextual Notes

Some participants reiterate the importance of using standard notation for trigonometric functions, which may influence clarity in communication. The repeated nature of the homework statement suggests a focus on ensuring understanding of the differentiation process.

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Homework Statement



Let f(x) = (x2)/sin(x)2. Find f'(x).

Homework Equations



Chain rule, quotient rule

The Attempt at a Solution



f'(x) = [2xsin(x)2 - x22cos(x)2]/(sin(x)2)2
 
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char808 said:

Homework Statement



Let f(x) = (x2)/sin(x)2. Find f'(x).

Homework Equations



Chain rule, quotient rule

The Attempt at a Solution



f'(x) = [2xsin(x)2 - x22cos(x)2]/(sin(x)2)2

Derivative of sin(x)2 = cos(x)2*2x
 
f'(x) = [2xsin(x)2 - x22xcos(x)2]/(sin(x)2)2
 
BTW, the usual notation for (sin(x))2 is sin2(x).
 

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