Solving for Force Components: Magnitude & Direction | 640 N, 39° North of East

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SUMMARY

The force vector in question has a magnitude of 640 N and is directed at an angle of 39° north of east. The north-south component of this force is calculated using the sine function, yielding a value of 497.4 N, while the east-west component is derived from the cosine function, resulting in 402.8 N. The calculations are performed as follows: North-south component = sin(39°) * 640 N and East-west component = cos(39°) * 640 N. The user inquired about significant figures for inputting these values into WebAssign, specifically whether to round to 497 N and 403 N.

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A force vector has a magnitude 640 N and a direction of 39° north of east. Determine the magnitude and direction of the components of the force that point along the north-south line and along the east-west line.

North-south component:

East-west component:

I know that the direction of these two components are north and east, but for the magnitudes i got 497.4 and 402.8, respectively. I used cos(39)640 and sin(39)640. Please if anyone can help it would be greatly appreciated, this question is for a webassign. Thank you very much
 
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I have a feeling its a sig fig error...do I put 497 and 403 into webassign instead? I just really don't want to get this question wrong for something stupid...
 

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