Solving for Higher Order Derivatives: Explaining f(x)=cos2x and f^50 = f^2

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Homework Help Overview

The discussion revolves around the function f(x) = cos(2x) and the assertion that the 50th derivative of this function equals the 2nd derivative, f^50 = f^2. Participants are exploring the reasoning behind this relationship and the implications of derivative patterns in trigonometric functions.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the validity of the statement f^50 = f^2 and discussing the cyclical nature of derivatives for trigonometric functions. There is an exploration of how the relationship 50 = (12)(4) + 2 is used to justify this equality.

Discussion Status

The discussion is ongoing, with participants expressing confusion and seeking clarification on the reasoning behind the derivative relationships. Some have noted the cyclical behavior of derivatives for cos(x) but have not reached a consensus on the specific case of cos(2x).

Contextual Notes

There is an underlying assumption regarding the periodicity of derivatives for trigonometric functions, which some participants are questioning. The discussion also highlights a potential misunderstanding of the relationship between the derivatives of different trigonometric functions.

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Homework Statement



if f(x)=cos2x, how do we know that f^50 = f^2 ??

In the solution it states that because 50 = (12)(4) + 2, then f^50 = f^2.

What the??
 
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We don't know that f(50) = f(2) for the reason that it isn't true. If the function were f(x) = cos(x), it would be true, though, and this is easy enough to verify by taking a few derivatives and noticing the cyclical nature of these derivatives.
 
Okay, well how do they know that f^2 = f^50 for cosx simply by going 50 = (4)(12) + 2
 
Because it repeats every four times
cosx
-sinx
-cosx
sinx
cosx
 

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