Solving for Logarithmic Decrement in LCR Circuits

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The discussion focuses on solving the differential equation for charge Q in an LCR circuit, specifically finding the logarithmic decrement. The equation provided is LQ''(t) + RQ'(t) + (1/C)Q(t) = 0, with the goal of showing the charge ratio between successive maxima is exp(RTd/2L). Participants discuss the challenge of determining Td, with suggestions to find maxima by analyzing the cosine function in the solution. It is noted that while the maxima of the cosine function and the overall behavior of the solution are related, the exponential decay must also be considered for accuracy. The conversation emphasizes the importance of understanding the relationship between the decay constant and natural frequency in this context.
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Homework Statement



Basically, I have LQ''(t) + RQ'(t) + (1/C)Q(t)=0, and I'm supposed to

"Show that the ration of the charge Q between two successive maxima is given by exp(RTd/2L), where Td is the time between two successive maxima. The natural logarithm of this ration is called the logarithmic decrement.


Homework Equations



Dunno

The Attempt at a Solution



So I got a solution Q(t)=e(-Rt)/(2L) [ C1cos( (√(R2-4L/C) )/(2L)t) + C2sin( (√(R2-4L/C) )/(2L)t).

But I can't figure out how to find Td. I mean, I could always find t when dQ/dt=0; but then I'd have to plug two values of t back into Q(t) and find the difference, and ... So what's the right way to do this?
 
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First notice the sin & cos terms have the same argument & the choice of c1 & c2 will just choose an overall phase. So for this argument set c2 = 0.

Then the maxima will just be where cos is maximum and successive maxima will occur where the argument of cos has changed by 2pi
 
lanedance said:
First notice the sin & cos terms have the same argument & the choice of c1 & c2 will just choose an overall phase. So for this argument set c2 = 0.

Then the maxima will just be where cos is maximum and successive maxima will occur where the argument of cos has changed by 2pi

Not exactly. The max's don't agree with the max's of the cosine, but the right idea. To the OP, just look at e-btcos(at+c).
 
good pickup thanks - They will be pretty close when the natural frequency is much larger that the decay constant, but you do need to take the exponential into account
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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