Problem related to Coloumb's force

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The discussion centers on calculating the tension in two strings holding identical charged bodies in a zero-gravity environment, specifically within an orbiting satellite. Participants explore the forces acting on the bodies, including Coulomb's repulsive force and the tension in the strings, while noting that gravitational forces are negligible. The key question is how the distance "r" between the charges relates to the length of the strings, with the conclusion that "r" equals 2l due to the equilibrium position reached by the charges. The conversation emphasizes the importance of visualizing the forces and angles involved to understand the equilibrium state of the system. Ultimately, the tension in the strings is derived from the balance of forces, confirming the relationship between the charges' separation and the string lengths.
  • #51
gracy said:
The charges would be like the charges at the ends of string of length 2l
So how do you go from two charges attached to strings of length ##l## to the two charges being ##2l## apart?
 
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  • #52
DrClaude said:
So how do you go from two charges attached to strings of length ll to the two charges being 2l2l apart?
Angle will increase until it is 180 degrees?
 
  • #53
gracy said:
Angle will increase until it is 180 degrees?
Yes!

Can you see now why this is happening?
 
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  • #54
DrClaude said:
Can you see now why this is happening?
Because of repulsion between like charges
 
  • #55
gracy said:
Because of repulsion between like charges
Don't forget the tension in the string.

Are you satisfied that you understand the answer to your question "I want to know how to find "r"how r came out to be 2l?"
 
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  • #56
DrClaude said:
Can you see now why this is happening?
gracy said:
I don't know whether it is correct but i think tension force will be able to be split into one horizontal force and one vertical.The horizontal one would cancel the repulsive force.But one problem with this is then vertical force would be unbalanced so net force would be vertical so motion should be in vertical direction.
This vertical force is responsible for going from two charges attached to strings of length l to the two charges being 2l apart
And after that tension in string would be equal to the repulsive force which has the value of (1/4πε0)*q^2/4l^2
r being 2l
Right @DrClaude ?
 
  • #57
DrClaude said:
Are you satisfied that you understand the answer to your question "I want to know how to find "r"how r came out to be 2l?"
Seeking your "yes" in answer to my post #56 to be satisfied.
 
  • #58
gracy said:
This vertical force is responsible for going from two charges attached to strings of length l to the two charges being 2l apart
And after that tension in string would be equal to the repulsive force which has the value of (1/4πε0)*q^2/4l^2
r being 2l
Right @DrClaude ?
Yes. When the two strings become horizontal, there is no more vertical component of the force, and equilibrium is reached between repulsion and tension.

gracy said:
Seeking your "yes" in answer to my post #56 to be satisfied.
We not all in the same time zone, and I need to sleep from time to time :wink:
 
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