Solving for Maximum Value of h in \mu = \lambda h

  • Thread starter Thread starter Ted123
  • Start date Start date
  • Tags Tags
    Maximum Value
Click For Summary
SUMMARY

The discussion focuses on finding the maximum value of h in the equation \(\mu = \lambda h\) under the condition that \(|1+\mu + \frac{1}{2} \mu^2 + \frac{1}{6} \mu^3| < 1\). The key approach involves solving the equation \(1+\mu + \frac{1}{2} \mu^2 + \frac{1}{6} \mu^3 = 1\) to determine the intervals for \(\mu\). The solution identifies \(\mu = 0\) as a valid solution and emphasizes the need to explore additional intervals based on the properties of the cubic function.

PREREQUISITES
  • Understanding of cubic equations and their properties
  • Familiarity with real numbers and inequalities
  • Basic knowledge of calculus, particularly in finding intervals of solutions
  • Experience with algebraic manipulation and solving polynomial equations
NEXT STEPS
  • Study the properties of cubic functions and their graphs
  • Learn techniques for solving polynomial inequalities
  • Explore the implications of the Intermediate Value Theorem in cubic equations
  • Investigate the behavior of functions near critical points and inflection points
USEFUL FOR

Students studying calculus, mathematicians interested in polynomial functions, and anyone tackling optimization problems involving cubic equations.

Ted123
Messages
428
Reaction score
0

Homework Statement



I'm asked to find the maximum value of [itex]h[/itex] such that [itex]\mu = \lambda h\;\;(\lambda \in \mathbb{R})[/itex] satisfies: [tex]|1+\mu + \frac{1}{2} \mu ^2 + \frac{1}{6} \mu ^3| < 1[/tex]

The Attempt at a Solution



My hurdle is solving [itex]1+\mu + \frac{1}{2} \mu ^2 + \frac{1}{6} \mu ^3=1[/itex] to find the interval [itex]\mu\in (?,?)[/itex] which satisfies [tex]|1+\mu + \frac{1}{2} \mu ^2 + \frac{1}{6} \mu ^3| < 1[/tex]
 
Physics news on Phys.org
-1 from both sides, then obviously μ=0 is a solution, and from there you should be able to find the rest of the intervals using the fact it's a positive cubic.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
6
Views
3K
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K