Solving for Points in 4D Space with Nonnegative Integer Coordinates

Click For Summary

Homework Help Overview

The problem involves finding the number of points in 4-dimensional space with nonnegative integer coordinates that satisfy a specific equation. The context is combinatorial counting within the subject area of discrete mathematics.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various methods to approach the problem, including brute force enumeration of combinations and combinatorial formulas. Some participants question the feasibility of brute force due to its potential inefficiency.

Discussion Status

There is an ongoing exploration of different methods, with some participants suggesting combinatorial approaches. A specific combinatorial formula has been proposed, and there is acknowledgment of its correctness, though further generalization is being considered.

Contextual Notes

Participants are considering the implications of the problem in terms of combinatorial counting and the constraints of nonnegative integers. There is a focus on the mathematical formulation of the problem without resolving the overall solution.

mathmajor23
Messages
29
Reaction score
0

Homework Statement



How many points (x1,x2,x3,x4) in the 4-dimensional space with nonnegative integer coordinates satisfy the equation x1 + x2 + x3 + x4 = 10?

I'm not sure which method to use to start this problem. Any ideas?
 
Physics news on Phys.org
forget the 4D for the moment and consider all the ways you can add up numbers to get 10:

0+0+0+10 = 10
0+0+1+9 = 10
1+1+1+7 = 10
...

and next you consider for each 4 number sum and ask yourself how many 4D points can have coordinate points of 1,1,1,7:
(1,1,1,7) (1,1,7,1) (1,7,1,1) (7,1,1,1)
 
That will take forever to use brute force.

Thinking combinatorially, my initial thought would be C(10+4-1,3) = C(13,3) = 286 different ways. Any thoughts?
 
mathmajor23 said:
That will take forever to use brute force.

Thinking combinatorially, my initial thought would be C(10+4-1,3) = C(13,3) = 286 different ways. Any thoughts?
That's correct.

More generally, can you show that the number of solutions to ##x_1 + x_2 + \cdots + x_k = n## with each x_i a nonnegative integer is C(n+k-1,k-1)?
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K