Solving for Power Dissipation in a Complex Circuit

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SUMMARY

The discussion focuses on calculating the power dissipated by an 8 ohm resistor in a complex circuit using source transformations. The user successfully transformed a 1 amp current source and a 20 ohm resistor into a 20 V voltage source in series with a 20 ohm resistor, resulting in an equivalent resistance of 40 ohms. The user also converted a 10 V voltage source and a 10 ohm resistor into a 1 amp current source in parallel with a 10 ohm resistor. To find the power dissipated by the 8 ohm resistor, the user is advised to apply Kirchhoff's Current Law (KCL) at the circuit nodes.

PREREQUISITES
  • Understanding of source transformations in electrical circuits
  • Familiarity with Kirchhoff's Current Law (KCL)
  • Knowledge of power calculations using the formulas P=VI, P=V^2/R, and P=I^2R
  • Basic circuit analysis techniques including series and parallel resistor combinations
NEXT STEPS
  • Learn detailed applications of Kirchhoff's Current Law (KCL) in circuit analysis
  • Study source transformation techniques for simplifying complex circuits
  • Explore power dissipation calculations in resistive circuits
  • Review examples of circuit analysis involving parallel and series resistors
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing power dissipation in electrical circuits.

electronicxco
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Homework Statement



Find the power dissipated by the 8 ohm resistor.
2v2ckxz.jpg

This was an example for source transformations.



Homework Equations


P=VI=V^2/r=I^2*R
V=IR



The Attempt at a Solution


First I transformed the 1 amp current source and 20 ohm in parallel
to a 20 V voltage source and a 20 ohm in series .
Then I added the two 20 ohms now in series for Req= 40 ohms.
Then I converted the 10 volt voltage source and the 10 ohm in series to a 1 amp current source in parallel with a 10 ohm resistor.

Now I am stuck , I don't feel like I should get the equiv.resistance of the 8 and 10 ohm resistors left in parallel ( because its asking for the power dissipated by the 8)

Can someone please guide me through this problem, what I'm doing wrong, or the proper approach.

Thank you
 
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electronicxco said:

Homework Statement



Find the power dissipated by the 8 ohm resistor.
2v2ckxz.jpg

This was an example for source transformations.



Homework Equations


P=VI=V^2/r=I^2*R
V=IR



The Attempt at a Solution


First I transformed the 1 amp current source and 20 ohm in parallel
to a 20 V voltage source and a 20 ohm in series .
Then I added the two 20 ohms now in series for Req= 40 ohms.
Then I converted the 10 volt voltage source and the 10 ohm in series to a 1 amp current source in parallel with a 10 ohm resistor.

Now I am stuck , I don't feel like I should get the equiv.resistance of the 8 and 10 ohm resistors left in parallel ( because its asking for the power dissipated by the 8)

Can someone please guide me through this problem, what I'm doing wrong, or the proper approach.

Thank you

Just write the 2 KCL equations on the circuit that you show, and solve. Call the bottom of the circuit ground, and write the KCL for the two nodes at the tops of the two vertical resistors.
 

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