Solving for Power & Speed: A Homework Challenge

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The homework challenge involves calculating the power after traveling 8 km, given that power is halved every 2 km from an initial power of 10 watts. After 8 km, the power would be reduced to 0.625 watts. Additionally, the speed of light in optical fiber is questioned, with the refractive index (n) provided as 1.55. The speed of light in a vacuum is approximately 3 x 10^8 m/s, which can be adjusted for the refractive index to find the speed in fiber. The discussion highlights the need for a formula to relate power and distance.
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Homework Statement


Every 2km power is reduced by half. Initial power = 10watt. What is power after traveled 8km?

C = 3x108. What is speed of light passing through optic fibre? n = 1.55

Homework Equations



P = \frac{w}{T} ?

The Attempt at a Solution


I don't know where to start
 
Last edited:
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Write a formula relating power and distance.....
P = 10(2-km/2)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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