Solving for Simple Harmonic Motion: A Picture Problem

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SUMMARY

The discussion focuses on proving that the equation for ##\theta(t)## represents simple harmonic motion (SHM) and determining its period. The equation follows the standard form of SHM, ##\ddot y=-\omega^2 y##, where ##\omega## is a real constant. Participants emphasize that any equation in this form describes SHM and suggest using the general solution to deduce the motion's period. Understanding this relationship is crucial for analyzing oscillatory systems.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear equations.
  • Familiarity with the concept of angular frequency (##\omega##) in oscillatory motion.
  • Knowledge of the general solution for simple harmonic motion.
  • Basic grasp of the relationship between displacement, velocity, and acceleration in SHM.
NEXT STEPS
  • Study the general solution of simple harmonic motion equations.
  • Learn how to derive the period of motion from the angular frequency (##\omega##).
  • Explore applications of simple harmonic motion in physical systems, such as springs and pendulums.
  • Investigate the effects of damping on simple harmonic motion.
USEFUL FOR

Students of physics, engineers working with oscillatory systems, and anyone interested in the mathematical foundations of simple harmonic motion.

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Homework Statement
An electric dipole lying in the xy-plane with a uniform electric field applied in the positive x-direction is displaced by a small angle ##\theta## from its equilibrium position. The charges are separated by a distance ##2a##. The moment of inertia of the dipole about the center of mass is ##I_{cm}##.

If the dipole is released from this position, show that its angular orientation exhibits simple harmonic motion. What is the period of oscillation?
Relevant Equations
$$\vec{\tau}=-2aE_x\sin{\theta} \hat{k}$$

$$\tau_z=I_{cm}\alpha_z$$

$$\alpha_z=\frac{\tau_z}{I_{cm}}=\frac{-2aE_x\sin{\theta}}{I_{cm}}=-B\sin{\theta}$$

where $$B=\frac{2aE_x}{I_{cm}}$$

This is a differential equation. I think that solving this equation would provide the correct result, but I don't want to go this route.

One route is, if ##\theta## is small, to use the approximation ##\sin{\theta}\approx\theta##.

Then

$$\alpha_z(t)=\theta''(t)=-B\theta(t)$$

I think this is the differential equation representing a simple harmonic motion of an ideal spring with

$$B=\frac{k}{m}$$
Here is a picture of the problem

1674603667180.jpeg


It is not clear to me how to really prove that the equation for ##\theta(t)## is simple harmonic motion, and what the period of this motion is.
 
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Your equation is the equation for simple harmonic motion which is of the form ##~\ddot y=-\omega^2 y~## where ##\omega## is a real constant and the differentiation is with respect to time. Any equation in that form describes simple harmonic motion. Do you know what the most general solution of that is? If so, plug it in and you should be able to deduce the period of the motion.
 

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