Solving for Spring Constant of Oscillating Spring

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SUMMARY

The discussion focuses on calculating the spring constant for a mass-spring system where a 7.0 kg mass oscillates with a period of 2.6 seconds. The user correctly applies the formulas for angular frequency (w = 2πf) and spring constant (k = mw²) to arrive at a spring constant of approximately 40.96 N/m. The calculations are confirmed as accurate, with minor rounding inaccuracies noted. The user also explores the relationship between force and displacement using Hooke's Law (F = -kx), but does not utilize displacement in their calculations.

PREREQUISITES
  • Understanding of basic physics concepts such as mass, oscillation, and spring dynamics.
  • Familiarity with the formulas for angular frequency and spring constant.
  • Knowledge of Hooke's Law (F = -kx) and its application in oscillatory motion.
  • Ability to perform basic algebraic manipulations and unit conversions.
NEXT STEPS
  • Learn about the derivation of the spring constant using different mass-spring systems.
  • Explore the effects of damping on oscillations in spring systems.
  • Investigate the relationship between frequency and spring constant in more complex oscillatory systems.
  • Study the principles of energy conservation in oscillating systems, including potential and kinetic energy transformations.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts related to spring dynamics and harmonic motion.

Glorzifen
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Homework Statement


A 7.0 kg mass is hung from the bottom end of a vertical spring fastened to the ceiling. The mass is set into veritcal oscillations with a period of 2.6s

Find the spring constant.

Homework Equations


w = [tex]\sqrt{k/m}[/tex]
w = 2pi * f
f = 1/T

The Attempt at a Solution


f = 1/T
= 1/2.6
= 0.385 Hz
w = 2pi * 0.385
= 2.42
w = [tex]\sqrt{k/m}[/tex]
w = k/7
5.85 = k/7
k = 40.96

Feel like my math could be wrong at the end there. Overall though, is this how its to be done? I tried using F = -kx...ma = -kx but I didn't have an 'x'.
 
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Yes that is how it should be done. Don't have a calculator to check your answers though.
 
There is some rounding inaccuracy but otherwise it is correct.

ehild
 

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