Solving for Volume Using the Shell Method

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Homework Help Overview

The discussion revolves around using the shell method to find the volume of solids generated by revolving a region defined by the equation x=18(y^2 - y^3) about the line y=8/5. Participants are exploring the setup and interpretation of the problem.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the setup of the shell method integral and question whether the region is properly defined, particularly regarding the boundaries of the region to be revolved. There are attempts to clarify the role of the y-axis in defining the bounded region.

Discussion Status

Some participants have provided guidance on the integral setup, noting the importance of including the differential in the expression. There is an ongoing exploration of the assumptions regarding the bounded region and the implications for the integral.

Contextual Notes

There is a mention of potential missing information regarding the boundaries of the region, specifically whether the y-axis is included in the setup. Participants are also considering the implications of omitting the differential in the integral.

whatlifeforme
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Homework Statement


use the shell method to find the volumes of the solids generated by revolving the region about the indicated axis.


Homework Equations


x=18(y^2 - y^3) about line y=8/5.


The Attempt at a Solution


2∏∫ (0 to 1) (8/5 - y) (18y^2 - 18y^3)
 
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whatlifeforme said:

Homework Statement


use the shell method to find the volumes of the solids generated by revolving the region about the indicated axis.


Homework Equations


x=18(y^2 - y^3) about line y=8/5.i
This single equation does not define a bounded region. Was there some other line or curve given, such as the y-axis (x= 0)?


The Attempt at a Solution


2∏∫ (0 to 1) (8/5 - y) (18y^2 - 18y^3)
 
according to the graph it appears bounded by y-axis. (x=0)
 
Assuming that the region to be revolved is between one arch of the curve and the y-axis, your setup looks fine, except that you are missing the differential. It might not seem important now, but when you learn more techniques of integration, omitting the differential will be a big problem.

whatlifeforme said:
2∏∫ (0 to 1) (8/5 - y) (18y^2 - 18y^3) dy[/color]



What do you get for the value of your integral?
 

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