Solving for x in 3^(log(base4)x)

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turutk
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Homework Statement



integrate 3^(log(base4)x)

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The Attempt at a Solution



i tried to write it in different ways. couldn't solve.
i tried to divide the whole thing by ln3 and then add some more constants to cancel out the remainings. still i could not cancel out the x in the denominator which comes from the chain rule.
 
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thank you very much for your help. at least i succeed
 
So you have to integrate

[tex]3^{x\ln 4}[/tex]

Then you'll have to integrate

[tex]\left(e^{\ln 3}\right)^{x\ln 4}[/tex]

which should be trivial, right ?

Unless you may have to integrate

[tex]3^\log_4 x[/tex]

in which case you have to integrate

[tex]\left(e^{\ln 3}\right)^{\frac{\ln x}{\ln 4}}[/tex]

which again should be trivial.