Solving Force & Mass Ratios: Find m1/m2 & Acceleration

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SUMMARY

The discussion focuses on solving a physics problem involving force, mass, and acceleration. Given a force F applied to two masses, m1 and m2, the acceleration produced is 3.0 m/s² for m1 and 1.0 m/s² for m2. The ratio m1/m2 is calculated to be 0.333, and when combined, the acceleration of the total mass (m1 + m2) under the same force is determined to be 0.75 m/s². The relationship F = ma is consistently applied throughout the solution process.

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bumblebeeliz
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Homework Statement



A force F applied to a mass m1 produces an acceleration of 3.0 m/s2. The same
force applied to a second object of mass m2 produces an acceleration of 1.0
m/s2.

a. Find the value of the ratio m1 / m2.
b. If m1and m2 are combined, what will be the acceleration of the combined mass (m1+ m2) under the action of the force F?


Homework Equations



F=ma

The Attempt at a Solution



a)

I didn't know where to begin. So I chose a random number and assumed that my force was 6 N.

6N = m1 a1
6N = m1 (3.0 m/s2)
6N / 3.0 m/s2 = m1
2 kg = m1

6N = m2 a2
6N = m1 (1.0 m/s2)
6N / 1.0 m/s2 = m2
6 kg = m2

m1/m2 = 2kg/6kg = 0.333 = 3 x 10 -1

b)

F = (m1+m2) a
6N = (2kg + 6kg) a
6N / 8kg = a
0.75 m/s2 = a

---

Any suggestions? :)
 
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bumblebeeliz said:
a)

I didn't know where to begin. So I chose a random number and assumed that my force was 6 N.

6N = m1 a1
6N = m1 (3.0 m/s2)
6N / 3.0 m/s2 = m1
2 kg = m1

6N = m2 a2
6N = m1 (1.0 m/s2)
6N / 1.0 m/s2 = m2
6 kg = m2

m1/m2 = 2kg/6kg = 0.333 = 3 x 10 -1

While this is correct. You didn't need to say F=6. It said the it applied the same force so F1=F2
or simply put m1a1=m2a2


bumblebeeliz said:
b)
F = (m1+m2) a
6N = (2kg + 6kg) a
6N / 8kg = a
0.75 m/s2 = a

---

Any suggestions? :)

So if F is the same, either F=m1a1 or F=m2a2


So you want F=(m1+m2)a . So you can put F equal to which either one you want and solve from there.
 
Makes more sense! Thanks :)
 

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