Solving Gaussian Elimination Homework

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Homework Help Overview

The discussion revolves around a Gaussian elimination problem involving a matrix setup with 17 rows. Participants are trying to understand how to structure the matrix A and vector b based on the given equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning how to determine the number of columns in matrix A and the values for each row. There is confusion about whether each equation corresponds to a single row or if multiple variables should be included in each row.

Discussion Status

There is ongoing exploration of the structure of the matrix and vector, with some participants providing insights into the relationship between the equations and the matrix setup. However, there is no explicit consensus on the correct interpretation of the problem.

Contextual Notes

Participants are grappling with the requirement that matrix A must have 17 columns to correspond with the 17 equations, while also trying to clarify the role of the variables F1 through F17 in the equations.

XodoX
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Homework Statement



http://img189.imageshack.us/i/50468910.png/


Homework Equations





The Attempt at a Solution



I'm wondering how I do this? I don't really know. Supposed to be 17 rows. How many columns and how many each row? No clue! And how do I get the numbers for the matrix here?
 
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Hi XodoX! :smile:
XodoX said:
I'm wondering how I do this? I don't really know. Supposed to be 17 rows. How many columns and how many each row? No clue! And how do I get the numbers for the matrix here?

The question says "the matrix A and b to have 17 rows" …

well, if Ab makes sense, that means A must have 17 columns, doesn't it? :wink:

(And there's 17 equations given so it's one row for each equation.)
 
Oh, ok. I thought one row for each joint. So, the first row would be -1, +1, +1 , which would be A, and 0 would be b. Is that correct?

Also, line # 4 says : F=f3-10=0 I suppose I have to move the 10 here, because all the other rows don't have numbers in them.
 
Last edited:
Hi XodoX! :wink:
XodoX said:
Oh, ok. I thought one row for each joint. So, the first row would be -1, +1, +1 , which would be A, and 0 would be b. Is that correct?

Also, line # 4 says : F=f3-10=0 I suppose I have to move the 10 here, because all the other rows don't have numbers in them.

No, your equation is Ab = c, where b is (f1,…f17), and c contains all the 0s and 10s and 15.

So the first row is … ? :smile:
 
tiny-tim said:
Hi XodoX! :wink:No, your equation is Ab = c, where b is (f1,…f17), and c contains all the 0s and 10s and 15.

So the first row is … ? :smile:
Sorry, I don't get it. I thought each equation is one row.. F1, F4, and F5 in the first row. If that's not it, I don't get it then. -F1 + F4 + F5 =0
 
XodoX said:
Sorry, I don't get it. I thought each equation is one row.. F1, F4, and F5 in the first row.

Yes, but there's 17 numbers in the first row (and every row), not just 3. :smile:
 
tiny-tim said:
Yes, but there's 17 numbers in the first row (and every row), not just 3. :smile:


But it says it has 17 rows, so I figured it must be the F values and numbers of each line for each row.

1. row -F1 + F4 + F5=0

2. row -F1 - F3 - F5 = 0

etc. :confused:
 
Hi XodoX! :smile:

(just got up :zzz: …)

No, the matrix A (and the vector c) only has numbers, not Fs … the Fs are only in the vector b.

For example, the first row of A is (-1,0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0). :wink:

(and so -F1 + F4 + F5 is the first row of the vector Ab, which has to be equal to the first row of the vector c, which of course is 0)
 
tiny-tim said:
Hi XodoX! :smile:

(just got up :zzz: …)

No, the matrix A (and the vector c) only has numbers, not Fs … the Fs are only in the vector b.

For example, the first row of A is (-1,0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0). :wink:

(and so -F1 + F4 + F5 is the first row of the vector Ab, which has to be equal to the first row of the vector c, which of course is 0)


Hi.

I know it doesn't have F's. Just did it because I thought it would better illustrate what I meant. I honestly don't know where you got the 17 numbers from. From what I see, it should be 17 rows down, and each rown has about 3-4 numbers. I understand that row 1 is -F1 + F4 + F5 and then the 0. But that's just 4 numbers and not 17 for this particular row.:confused: Sorry, I don't know why this seems so difficult. It's actually not.
 
  • #10
Each row of A, when multiplied by b, gives you the LHS of one of the equations.

For example, the row I gave you, multiplied by b = (F1, … F17), gives you the LHS of equation #1 …

I don't understand why you don't see that. :confused:
 
  • #11
What's there to multiply b ? b is 0 there. It's already on the right side of the equation. Why would I even multiply by b?
 
  • #12
I don't think we're talking about the same thing :confused:

I'm talking about an equation Ab = c,

where A is a matrix with numbers (mostly 0), b is the vector (F1, …F17), and c is a vector with 0s 10s and 15s
 

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