Solving Hockey Puck Friction Problem

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Homework Help Overview

The discussion revolves around a physics problem involving a hockey puck sliding on ice, where participants explore concepts of acceleration and friction. The original poster presents a scenario where the puck's speed decreases over time, prompting questions about calculating average acceleration and the coefficient of kinetic friction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between acceleration and friction, with some questioning the need for mass in calculations. There is a focus on how to express the frictional force and its relationship to acceleration.

Discussion Status

Some participants have provided insights into the equations involved, noting that mass cancels out in the context of the frictional force. This has led to further clarification on how to approach the problem without needing the mass explicitly.

Contextual Notes

There is an indication that the original poster initially felt confused about the use of mass in the calculations, and the discussion reflects an exploration of assumptions regarding the problem setup.

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Homework Statement



A hockey puck is hit on a frozen lake and starts moving with a speed of 12.0m/s. Exactly 5.0sec later, its speed is 6.0m/s. What is the puck's average acceleration? What is the coefficient of kinetic friction between the puck and ice?

Homework Equations


VF=VI+at
FN=mg
FF=UFN
FF=ma
EFY=FN+Fgcos(0)
(cos(0)=1)

The Attempt at a Solution


I have the acceleration it's -1.2m/s2 (that was easy been doing that for a while)The problem is I am having trouble on finding the coefficient of Friction. I'm pretty sure the last four equations are correct, do i need to find Fn next? Because i don't have the mass and it's not moving at a constant velocity, so i do need mass right?if and multiply that by gravity to get Fn? All I know i have the info just a little confused on how to use itNever mind i got it no worry's
 
Last edited:
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If you solve the equation for FF=ma, you'll find that the m's cancel out.
 


uh? what do u mean m's cancel out? The mass cancels out? and you that's one formula forgot (i edited it in)
 


Yes. You'll find that writing the frictional force in terms of m,g, and u and setting it equal to ma will result in the masses canceling out.
 


edit: yep ^^^^^^^^

I believe he/she means that you can replace m*a for the force of friction, so:

-1.2m = k*-9.81m

By solving this, you see that the mass cancels and you're left with the coefficient of friction.
 

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