Solving Ideal Gas Law: Find Final Volume of Helium

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SUMMARY

The discussion focuses on solving the Ideal Gas Law to find the final volume of helium gas under specific conditions. Given two moles of helium at an initial temperature of 187 K and pressure of 0.33 atm, the gas is compressed isothermally to a final pressure of 0.57 atm. The correct final volume calculation, using the Ideal Gas Law formula, results in a value of 0.005455 m³, correcting the initial miscalculation due to decimal placement errors.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of isothermal processes in thermodynamics
  • Familiarity with unit conversions (atm to Pa, m³ to liters)
  • Basic algebra for solving equations
NEXT STEPS
  • Review the Ideal Gas Law and its applications in real-world scenarios
  • Learn about isothermal processes and their implications in gas behavior
  • Practice unit conversions between different measurement systems
  • Explore common errors in scientific calculations and how to avoid them
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Students in chemistry or physics, engineers working with gas systems, and anyone interested in thermodynamic principles and calculations.

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Given: R=8.31451 J/(K*mol)

Two moles of helium gas initially at 187 K and 0.33 atm are compressed isothermally to 0.57 atm.
Find the final volume of the gas. Assume the helium to behave as an ideal gas. Answer in units of m^3.

I've tried this many many times and i keep getting 5.455 which is not right. can someone please help? Thanks
 
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Check your powers of ten (decimal placements).
 
thanks a lot

I got it thanks.
 

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