Solving Incline Problem Homework: Find Distance & PE

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SUMMARY

The discussion focuses on solving a physics problem involving a toy cart of mass 5 kg projected up a 30-degree incline with an initial velocity of 6 m/s and a frictional force of 4 N. The user initially miscalculated the net force and acceleration, leading to an incorrect distance traveled before stopping. The correct approach requires accounting for both gravitational and frictional forces to determine the net force acting on the cart. Additionally, the user expressed interest in solving the problem using the conservation of energy principle.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of kinematic equations (v² = v₁² + 2ad)
  • Familiarity with free body diagrams
  • Concept of gravitational potential energy
NEXT STEPS
  • Review the calculation of net forces on an inclined plane
  • Learn about gravitational potential energy and its calculation
  • Study the conservation of energy principle in mechanics
  • Practice solving problems involving friction on inclined planes
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Students studying physics, particularly those tackling mechanics problems involving forces, energy conservation, and inclined planes.

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Homework Statement


a toy cart of mass 5kg is projected up a ramp incined at 30 degree to the horizontal, with an initial velocity of 6m/s. if the frictional force opposing its motion is 4N, find the distance it travels before stopping, and its increase in gravitational potential energy at that point.


Homework Equations


F=ma
v2^2 = v1^2 + 2ad

The Attempt at a Solution


so using vector, mgsin30 - 2 = ma
24.5 = 5a
a=4.9m/s^2

sub into
v2^2 = v1^2 + 2ad
and i got 36/1.8 = 20 = d but it is very different from answer of the book
please help me to solve it
 
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kokok said:

Homework Statement


a toy cart of mass 5kg is projected up a ramp incined at 30 degree to the horizontal, with an initial velocity of 6m/s. if the frictional force opposing its motion is 4N, find the distance it travels before stopping, and its increase in gravitational potential energy at that point.


Homework Equations


F=ma
v2^2 = v1^2 + 2ad

The Attempt at a Solution


so using vector, mgsin30 - 2 = ma
24.5 = 5a
a=4.9m/s^2

sub into
v2^2 = v1^2 + 2ad
and i got 36/1.8 = 20 = d but it is very different from answer of the book
please help me to solve it


Why do you have that as 2? It says the force of friction is 4 N. By the way, if the cart is being pushed up the ramp, the frictional force and the gravitational force act in the same direction. So how does that change things? Did you draw a free body diagram?
 
kokok said:

The Attempt at a Solution


so using vector, mgsin30 - 2 = ma
24.5 = 5a
a=4.9m/s^2
You'll need to redo this calculation. Your initial equation is not quite right. What forces act on the cart? (Include both gravity and friction.) In which direction do those forces act? What's the net force acting on the cart?
 
oh thank you, now i get this question..what a silly mistake i made..
 
omg. it's the same problem that I am working on right now.

but i need to solve it using the concept of conservation of energy. anyone knows how?
 
a seeker said:
omg. it's the same problem that I am working on right now.

but i need to solve it using the concept of conservation of energy. anyone knows how?

What have you tried? Show some of your work.
 

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