Solving Isobaric Process Heat Addition Problem

In summary, the change of temperature for a monatomic ideal gas when 610 J of heat is added at constant pressure is 21.5 K. However, this calculation does not take into account the increase in internal energy, and using the specific heat at constant pressure (Cp) for a monatomic gas of 5/2R, the change in temperature is actually 8.63 K.
  • #1
yankees26an
36
0
NVM I solved it. Thanks for reading anyway :)

Homework Statement


610 J of heat is added to 3.4 mol of a monatomic ideal gas at constant pressure. Find the
change of temperature of the gas.

Homework Equations


At isobaric conditions, w = p[tex]\Delta[/tex]V = nR[tex]\Delta[/tex]T

w = nR[tex]\Delta[/tex]T

The Attempt at a Solution



w = 610 J; n = 3.4

610/(3.4*8.314) = 21.5 K = [tex]\Delta[/tex]T

Calculations look right to me,but the answer is 8.63 K
 
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  • #2
yankees26an said:
NVM I solved it. Thanks for reading anyway :)

Homework Statement


610 J of heat is added to 3.4 mol of a monatomic ideal gas at constant pressure. Find the
change of temperature of the gas.


Homework Equations


At isobaric conditions, w = p[tex]\Delta[/tex]V = nR[tex]\Delta[/tex]T

w = nR[tex]\Delta[/tex]T


The Attempt at a Solution



w = 610 J; n = 3.4

610/(3.4*8.314) = 21.5 K = [tex]\Delta[/tex]T

Calculations look right to me,but the answer is 8.63 K
You are equating Q with W. That is true only if the internal energy does not change, which of course is not the case when temperature increases.

The 610 joules of heat flow does two things: causes the gas to do work and increases its internal energy.

The specific heat at constant pressure is the heat flow per degree of temperature rise (per mole) of a monatomic gas during a constant pressure process:

[tex]\Delta Q = nC_p\Delta T[/tex]

Use that to calculate the change in temperature. What is Cp for a monatomic gas?

AM
 
  • #3
Andrew Mason said:
You are equating Q with W. That is true only if the internal energy does not change, which of course is not the case when temperature increases.

[tex]\Delta Q = nC_p\Delta T[/tex]

Use that to calculate the change in temperature. What is Cp for a monatomic gas?

AM

Yea I realized that and used the other equation after some trial and error. Cp for a monoatomic gas is 5/2R :)

Solved.
 

Related to Solving Isobaric Process Heat Addition Problem

What is an isobaric process?

An isobaric process is a thermodynamic process in which the pressure remains constant while other parameters, such as volume and temperature, may change.

What is the purpose of solving isobaric process heat addition problems?

The purpose of solving isobaric process heat addition problems is to understand and analyze the changes in thermodynamic properties, such as temperature and volume, when heat is added to a system at a constant pressure.

What are the key steps to solving an isobaric process heat addition problem?

The key steps to solving an isobaric process heat addition problem are: identifying the system, determining the initial and final states of the system, applying the first law of thermodynamics, and solving for the unknown properties.

What are some common applications of isobaric processes?

Isobaric processes are commonly found in everyday life, such as in the operation of a pressure cooker, gas turbine engines, and refrigeration systems.

What are some challenges in solving isobaric process heat addition problems?

Some challenges in solving isobaric process heat addition problems include accurately identifying the system and its boundaries, accounting for all forms of energy transfer, and dealing with non-ideal conditions or assumptions in the calculations.

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