Solving LC-Circuit Problem: Q & I as Func. of Time

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In the discussion about solving an LC-circuit problem, the user is tasked with deriving expressions for charge (Q) and current (I) as functions of time, given specific initial conditions. Despite attempts to match their solution with the book's answers, discrepancies arise, particularly with the phase displacement (phi) and the initial current value. The user believes the book's answer is incorrect based on their calculations, which align with the initial conditions provided. Another participant suggests solving the differential equation directly rather than relying on memorized formulas, emphasizing the importance of understanding the underlying concepts. The user expresses confidence in their solution after verifying it against the initial conditions.
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Homework Statement




In an LC-circuit, with:

L = 64 mH
C = 121 nF

where at t=0,

Q = 10*10^-6 C , (the charge on the capasitor)
I = 0,3 A, (the current through the inductor)

Write an expression for the charge on the capacitor and the current through the inductor as a function of time.

The Attempt at a Solution



I've tried this several times from stratch now, and while I do get an answer, according to the book I'm wrong. The standard form of a solution for Q, is Q = Qm*cos(wt + phi), where phi is the phase displacement. My strategy is to write both the expressions for Q and I, both containing the unknown parameters phi and Qm, and solving the system of two equations with two unknowns.

However, I always get phi = -1,20, whereas the answer in the book is phi = -0,922. I've attached my latest handwritten attempt at a solution, thanks for any help!
 

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Update:

I decided to check the answer in the book. The answer the book gives for the current function is:

I = 0,642*cos(Wt + pi/2 - 0,922), where w = 1,14*10^4

However, when setting t=0, this function gives an output I of 0,511. That is not equal to the problem's initial condition of I = 0,3!

The answer I got after substituting the variables back is:

I = 0,322*cos(wt + pi/2 - 1,2), where w = 11364

which coincidentally checks out as I = 0,3 when t=0.

I therefore conclude that the book is wrong, but I still would very much like a second opinion on this one. This is my first LC-circuit problem, so it's really hard to be too confident in my calculations.

Would greatly appreciate any help! :)
 
Your differential equation is wrong. The solution of LQ"-Q/C=0 is not periodic at all. There should be "+" instead of "-". ehild
 
Try solving it directly using differential equation rather than using the derived formula. It is always easier and better to understand and solve the equations rather than memorizing formulae.

This will help. http://en.wikipedia.org/wiki/LC_circuit
 
You are correct, but it's just a typo, I solved it as if it were a plus. Anyway, I do know how to solve this differential equation. What I thought gave me trouble was solving for the initial conditions, but seeing how the answer in the book didn't check out when I tested it, whereas mine did, I actually do believe I got the right answer from the beginning.

Thanks for replying!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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