Solving Linear System with Gaussian Elimination - Help for Beginner

Click For Summary
To solve the given linear system using Gaussian elimination, start by selecting a pivot, ideally a coefficient of 1, to simplify calculations. The equations should be arranged in a consistent order to facilitate elimination of variables. It is recommended to represent the system as an augmented matrix for clarity, although it is not strictly necessary. The discussion also includes a LaTeX code snippet for creating matrices, which can help visualize the problem. Overall, the key steps involve proper organization of equations and careful elimination of variables to reach a solution.
shane1
Messages
7
Reaction score
0
I've taken about 3 year break from this style of math, I've been doing Calculus since then. I am taking a beginning linear algebra course and I have a system I have to solve with Gaussian Elimination. I know how to work towards a solution and what Gaussian Elimination is. However when I look at this one I just can not see how to start it up.

Oh yea, the system is:
x + 2y - z = 4
y - z = 3
x + 3y =2z = 7
2u + 4w + x +7y = 7

Also if someone on here would be able to post the code for how to get Latex to display it is an augmented matrix I'd be really greatful.

I feel with this I just need a kick in the right direction.

-Shane
 
Last edited:
Physics news on Phys.org
Pick a pivot. In this it looks like a good choice is x in the x + 2y - z = 4. Then eliminate all other variables in that position. The other rows containing an x are x + 3y + 2z = 7 and 2u + 4w + x + 7y = 7.

It would be easier to do if you had it in a matrix so that the variables are all in order, from x to z.
 
i found this latex code for a matrix:

[tex ]V = \left( \begin{array}{ccc}1-\frac{1}{2}\lambda^2 & \lambda & A\lambda^3(\rho-i\eta) \\-\lambda & 1-\frac{1}{2}\lambda^2 & A\lambda^2 \\A\lambda^3(1-\rho-i\eta) & -A\lambda^2 & 1\end{array} \right)[/tex]

which produces this

V = \left( \begin{array}{ccc}1-\frac{1}{2}\lambda^2 & \lambda & A\lambda^3(\rho-i\eta) \\-\lambda & 1-\frac{1}{2}\lambda^2 & A\lambda^2 \\A\lambda^3(1-\rho-i\eta) & -A\lambda^2 & 1\end{array} \right)

it's not augmented but i think it still works. it's not necessary to augment your matrices but it might help to remember where the numbers are on one side of the equations. i don't like to augment my matrices because i always forget that there are numbers over there & then i don't do the operations on them.

as orthodentist said, the first thing you've got to do is pick a pivot. i would go with one that has 1 as its coefficient because it saves a lot of work. it's easier to multiply things by multiples of 1 than some other number or a fraction. then you've got to decide what order you want the other variables in. & you've got to make sure all the equations are written with them in the same order. & don't forget that the coefficient of a certain variable is 0 when it doesn't appear in an equation!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
4
Views
2K
Replies
12
Views
9K
Replies
2
Views
2K