Solving Logarithmic Equations for Homework Help

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Homework Help Overview

The discussion revolves around solving a logarithmic equation involving multiple logarithmic terms. Participants are examining the validity of the equation and exploring properties of logarithms.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to simplify the logarithmic expression but expresses uncertainty about the next steps. Some participants reference properties of logarithms, such as the product and quotient rules, while others question the clarity of notation used in the expressions.

Discussion Status

Participants are actively engaging with the problem, offering insights into logarithmic properties and seeking clarification on notation. There is a collaborative atmosphere, with some guidance provided regarding the application of logarithmic rules, though no consensus on the solution has been reached.

Contextual Notes

There is a noted concern about the notation used in the logarithmic expressions, particularly regarding the use of parentheses, which may affect interpretation. The original poster's attempts indicate a possible misunderstanding of logarithmic properties.

enibaraliu
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Is log49/4+log9/35-log21/10 = log2/3 ?

I've tried and I'm here 2log1/5+2log2/5-log7=log2/4 , if I didn't do anything wrong, but I don't know what to do then , please help me !
 
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log(a) + log(b) = log(ab) is one of the useful properties of logarithms
 


enibaraliu said:
Is log49/4+log9/35-log21/10 = log2/3 ?

I've tried and I'm here 2log1/5+2log2/5-log7=log2/4 , if I didn't do anything wrong, but I don't know what to do then , please help me !
Please use parentheses! Does "log1/5" mean log(1/5) or log(1))/5? And please show how you got that result.
 
Hi enibaraliu! :smile:
enibaraliu said:
Is log49/4+log9/35-log21/10 = log2/3 ?

I've tried and I'm here 2log1/5+2log2/5-log7=log2/4 , if I didn't do anything wrong, but I don't know what to do then , please help me !

erm :redface: … log A + log B = log AB

log A - log B = log A/B

Try again! :smile:
 

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